2 # Get modification time of a file or directory and pretty-print it.
3 # Copyright (C) 1995, 1996, 1997 Free Software Foundation, Inc.
4 # written by Ulrich Drepper <drepper@gnu.ai.mit.edu>, June 1995
6 # This program is free software; you can redistribute it and/or modify
7 # it under the terms of the GNU General Public License as published by
8 # the Free Software Foundation; either version 2, or (at your option)
11 # This program is distributed in the hope that it will be useful,
12 # but WITHOUT ANY WARRANTY; without even the implied warranty of
13 # MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
14 # GNU General Public License for more details.
16 # You should have received a copy of the GNU General Public License
17 # along with this program; if not, write to the Free Software Foundation,
18 # Inc., 59 Temple Place - Suite 330, Boston, MA 02111-1307, USA.
20 # Prevent date giving response in another language.
28 # Get the extended ls output of the file or directory.
29 # On HPUX /bin/sh, "set" interprets "-rw-r--r--" as options, so the "x" below.
30 if ls -L /dev
/null
1>/dev
/null
2>&1; then
31 set - x
`ls -L -l -d $1`
35 # The month is at least the fourth argument
36 # (3 shifts here, the next inside the loop).
41 # Find the month. Next argument is day, followed by the year or time.
47 Jan
) month
=January
; nummonth
=1;;
48 Feb
) month
=February
; nummonth
=2;;
49 Mar
) month
=March
; nummonth
=3;;
50 Apr
) month
=April
; nummonth
=4;;
51 May
) month
=May
; nummonth
=5;;
52 Jun
) month
=June
; nummonth
=6;;
53 Jul
) month
=July
; nummonth
=7;;
54 Aug
) month
=August
; nummonth
=8;;
55 Sep
) month
=September
; nummonth
=9;;
56 Oct
) month
=October
; nummonth
=10;;
57 Nov
) month
=November
; nummonth
=11;;
58 Dec
) month
=December
; nummonth
=12;;
64 # Here we have to deal with the problem that the ls output gives either
65 # the time of day or the year.
67 *:*) set `date`; eval year
=\$
$#
82 # For the first six month of the year the time notation can also
83 # be used for files modified in the last year.
84 if (expr $nummonth \
> $nummonthtod) > /dev
/null
;
92 echo $day $month $year
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