*index = i;
}
+/*
+ * Try to remove refcount tree. The mechanism is:
+ * 1) Check whether i_clusters == 0, if no, exit.
+ * 2) check whether we have i_xattr_loc in dinode. if yes, exit.
+ * 3) Check whether we have inline xattr stored outside, if yes, exit.
+ * 4) Remove the tree.
+ */
+int ocfs2_try_remove_refcount_tree(struct inode *inode,
+ struct buffer_head *di_bh)
+{
+ int ret;
+ struct ocfs2_inode_info *oi = OCFS2_I(inode);
+ struct ocfs2_dinode *di = (struct ocfs2_dinode *)di_bh->b_data;
+
+ down_write(&oi->ip_xattr_sem);
+ down_write(&oi->ip_alloc_sem);
+
+ if (oi->ip_clusters)
+ goto out;
+
+ if ((oi->ip_dyn_features & OCFS2_HAS_XATTR_FL) && di->i_xattr_loc)
+ goto out;
+
+ if (oi->ip_dyn_features & OCFS2_INLINE_XATTR_FL &&
+ ocfs2_has_inline_xattr_value_outside(inode, di))
+ goto out;
+
+ ret = ocfs2_remove_refcount_tree(inode, di_bh);
+ if (ret)
+ mlog_errno(ret);
+out:
+ up_write(&oi->ip_alloc_sem);
+ up_write(&oi->ip_xattr_sem);
+ return 0;
+}
+
/*
* Given a cpos and len, try to find the refcount record which contains cpos.
* 1. If cpos can be found in one refcount record, return the record.