For now, we do not overload the `=' operator. */
int
-binop_user_defined_p (enum exp_opcode op, struct value *arg1, struct value *arg2)
+binop_types_user_defined_p (enum exp_opcode op,
+ struct type *type1, struct type *type2)
{
- struct type *type1, *type2;
if (op == BINOP_ASSIGN || op == BINOP_CONCAT)
return 0;
- type1 = check_typedef (value_type (arg1));
+ type1 = check_typedef (type1);
if (TYPE_CODE (type1) == TYPE_CODE_REF)
type1 = check_typedef (TYPE_TARGET_TYPE (type1));
- type2 = check_typedef (value_type (arg2));
+ type2 = check_typedef (type1);
if (TYPE_CODE (type2) == TYPE_CODE_REF)
type2 = check_typedef (TYPE_TARGET_TYPE (type2));
|| TYPE_CODE (type2) == TYPE_CODE_STRUCT);
}
+/* Check to see if either argument is a structure, or a reference to
+ one. This is called so we know whether to go ahead with the normal
+ binop or look for a user defined function instead.
+
+ For now, we do not overload the `=' operator. */
+
+int
+binop_user_defined_p (enum exp_opcode op,
+ struct value *arg1, struct value *arg2)
+{
+ return binop_types_user_defined_p (op, value_type (arg1), value_type (arg2));
+}
+
/* Check to see if argument is a structure. This is called so
we know whether to go ahead with the normal unop or look for a
user defined function instead.