Btrfs: merge inode_list in __merge_refs
authorAlexander Block <ablock84@googlemail.com>
Thu, 8 Nov 2012 21:27:24 +0000 (21:27 +0000)
committerJosef Bacik <jbacik@fusionio.com>
Wed, 12 Dec 2012 22:15:27 +0000 (17:15 -0500)
When __merge_refs merges two refs, it is also needed to merge the
inode_list of both refs. Otherwise we have missed backrefs and memory
leaks. This happens for example if two inodes share an extent and
both lie in the same leaf and thus also have the same parent.

Signed-off-by: Alexander Block <ablock84@googlemail.com>
Reviewed-by: Jan Schmidt <list.btrfs@jan-o-sch.net>
Signed-off-by: Chris Mason <chris.mason@fusionio.com>
fs/btrfs/backref.c

index a3219523ebc9a7f63783089fdf9302789673b9cb..04edf69be87561318375716abeb1d854370c63c3 100644 (file)
@@ -461,6 +461,7 @@ static int __merge_refs(struct list_head *head, int mode)
                     pos2 = n2, n2 = pos2->next) {
                        struct __prelim_ref *ref2;
                        struct __prelim_ref *xchg;
+                       struct extent_inode_elem *eie;
 
                        ref2 = list_entry(pos2, struct __prelim_ref, list);
 
@@ -472,12 +473,20 @@ static int __merge_refs(struct list_head *head, int mode)
                                        ref1 = ref2;
                                        ref2 = xchg;
                                }
-                               ref1->count += ref2->count;
                        } else {
                                if (ref1->parent != ref2->parent)
                                        continue;
-                               ref1->count += ref2->count;
                        }
+
+                       eie = ref1->inode_list;
+                       while (eie && eie->next)
+                               eie = eie->next;
+                       if (eie)
+                               eie->next = ref2->inode_list;
+                       else
+                               ref1->inode_list = ref2->inode_list;
+                       ref1->count += ref2->count;
+
                        list_del(&ref2->list);
                        kfree(ref2);
                }
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