m68k: fix memcpy to unmatched/unaligned source and dest on 68000
authorGreg Ungerer <gerg@uclinux.org>
Fri, 5 Aug 2011 04:41:29 +0000 (14:41 +1000)
committerGreg Ungerer <gerg@uclinux.org>
Tue, 18 Oct 2011 04:22:24 +0000 (14:22 +1000)
The original 68000 processors cannot copy 16bit or larger quantities from
odd addresses. All newer members of the 68k family (including ColdFire)
can do this.

In the current memcpy implementation after trying to align the destination
address to a 16bit boundary if we end up with an odd source address we go
off and try to copy multi-byte quantities from it. This will trap on the
68000.

The only solution if we end with an odd source address is to byte wise
copy the whole memcpy region. We only need to do this if we are supporting
original 68000 processors.

Signed-off-by: Greg Ungerer <gerg@uclinux.org>
arch/m68k/lib/memcpy.c

index 064889316974756878ff3a5f969068ab71b5cc2a..10ca051d56b83cd2b8c9263c01d8ef08cc7383e0 100644 (file)
@@ -22,6 +22,15 @@ void *memcpy(void *to, const void *from, size_t n)
                from = cfrom;
                n--;
        }
+#if defined(CONFIG_M68000)
+       if ((long)from & 1) {
+               char *cto = to;
+               const char *cfrom = from;
+               for (; n; n--)
+                       *cto++ = *cfrom++;
+               return xto;
+       }
+#endif
        if (n > 2 && (long)to & 2) {
                short *sto = to;
                const short *sfrom = from;
This page took 0.024888 seconds and 5 git commands to generate.